Class 7 Maths Chapter 2 Exercise 2.7 Pdf Notes NCERT Solutions

Class 7 Maths Chapter 2 Fractions and Decimals Exercise 2.7 pdf notes:-

Class 7 Maths Chapter 2 Exercise 2.7 Pdf Notes

Exercise 2.7 Class 7 maths Chapter 2 Pdf Notes:-

To see video Solution Of This Exercise Click Here

Ncert Solution for Class 7 Maths Chapter 2 Fractions and decimals Exercise 2.7 Tips:-

Join

DIVISION OF DECIMAL NUMBERS

Savita was preparing a design to decorate her classroom. She needed a few coloured
strips of paper of length 1.9 cm each. She had a strip of coloured paper of length 9.5 cm

Take 31.5 ÷ 10 = 3.15. In 31.5 and 3.15, the digits are
same i.e., 3, 1, and 5 but the decimal point has shifted in the
quotient. To which side and by how many digits? The decimal
point has shifted to the left by one place. Note that 10 has one
zero over 1.
Consider now 31.5 ÷ 100 = 0.315. In 31.5 and 0.315 the
digits are same, but what about the decimal point in the quotient?
It has shifted to the left by two places. Note that 100 has two zeros over1.
So we can say that, while dividing a number by 10, 100 or 1000, the digits of the
number and the quotient are same but the decimal point in the quotient shifts to the
left by as many places as there are zeros over 1. Using this observation let us now
quickly find: 2.38 ÷ 10 = 0.238, 2.38 ÷ 100 = 0.0238, 2.38 ÷ 1000 = 0.00238

Or, let us first divide 64 by 2. We get 32. There is one digit to the right of the decimal
point in 6.4. Place the decimal in 32 such that there would be one digit to its
right. We get 3.2 again.
To find 19.5 ÷ 5, first find 195 ÷5. We get 39. There is one digit to the
right of the decimal point in 19.5. Place the decimal point in 39 such that there
would be one digit to its righ

Answers

Leave a Comment

Your email address will not be published.