Class 8 Maths Chapter 9 Test Paper Set 4 Pdf Download CBSE

Test Paper Of Class 8 Maths Chapter 9 Algebraic Expressions and Identities set 4 pdf download

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Chapter 9 Test Paper (04)

Class 8 Maths Chapter 9 Algebraic Expressions and Identities Test Paper Set-4 Text Form:-

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SAMPLE PAPER (4)
CLASS: 8                                                MAX. MARKS :30
SUBJECT: MATHEMATICS                  TIME: 1:30 HOUR
CH: 9 (Algebraic Expressions and Identities)

Section – A

In Questions 1 to 10, there are four options, out of which one is correct. Write the correct answer.

1. The product of a monomial and a binomial is a

(a) monomial                    (b) binomial

(c) trinomial                      (d) none of these

2. If we subtract –3x2y2 from x2y2, then we get

(a) – 4x2y2                        (b) – 2x2y2

(c) 2x2y2                           (d) 4x2y2

3. Product of the following monomials 4p, – 7q3, –7pq is

(a) 196 p2q4                     (b) 196 pq4

(c) – 196 p2q4                  (d) 196 p2q3

4. Square of 3x – 4y is

(a) 9x2 – 16y2                  (b) 6x2 – 8y2

(c) 9x2 + 16y2 + 24xy     (d) 9x2 + 16y2 – 24xy

5. Coefficient of y in the term 3/βˆ’y is

(a) – 1                            (b) – 3

(c) -1/3                           (d)1/3

Section – B

6. Classify the following polynomials as monomials, binomials, trinomials. Which polynomials do not fit in any of these three categories?

x + y, 1000, x + x2 + x3+ x4, 7 + y + 5x, 2y – 3y2, 2y – 3y2 + 4y3, 5x – 4y + 3xy, 4z – 15z2,

7. Add (a) l2+ m2, m2 + n2, n2 + l2, 2lm + 2mn + 2nl

(b) Subtract 5x2– 4y2+ 6y – 3 from 7x2– 4xy + 8y2+ 5x 3y.

8. Obtain the product of

(a) 2, 4y, 8y2, 16y3

(b) pq + qr + rp, 0

9. Simplify a (a2 + a + 1) + 5 and find its value for

(i) a = 0,

(ii) a = 5

Section – C

10. Find the product.

(a) (2pq + 3q2) and (3pq – 2q2)

(b) (a + 7) and (b – 5)

(c) (a2+ 2b2) and (5a – 3b)

11. Simplify

(a) (2.5m + 1.5q)2 + (2.5m – 1.5q)

(b) (x2 – 4) (x2 + 4) + 16

12. Use a suitable identity to get each of the following products.

(a) (7a – 9b) (7a – 9b)

(b) (4x + 5) (4x + 1)

(c) (– a + c) (– a + c)

Section – D

13. Simplify.

(a) (a – b) (a + b) + (b – c) (b + c) + (c – a) (c + a) = 0

(b) (4m + 5n)2+ (5m + 4n)2

(c) 5.1 Γ— 5.2

(d) 712

14. (a) The cost of a chocolate is Rs (x + y) and Rohit bought (x + y) chocolates. Find the total amount paid by him in terms of x. If x = 10, find the amount paid by him.

(b) Subtract b (b2 + b – 7) + 5 from 3b2 – 8 and find the value of expression obtained for b = – 3.

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