NCERT Solutions For Class 6 Maths Chapter 10 Exercise 10.3

Ncert Solutions for Class 6 Maths Chapter 10 Mensuration Exercise 10.3:-

Exercise 10.3 Class 6 maths NCERT solutions Chapter 10 Mensuration pdf download:-

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SQUARES AND RECTANGLES:-

Ayush and Deeksha made pictures. Ayush made his picture on a rectangular sheet of length

60 cm and breadth 20 cm while Deeksha made hers on a rectangular sheet of length 40 cm

and breadth 35 cm. Both of these pictures have to be separately framed and laminated.

Who has to pay more for framing, if the cost of framing is ` 3.00 per cm?

If the cost of lamination is ` 2.00 per cm2,who has to pay more for lamination?

For finding the cost of framing, we need to find perimeter and then multiply it by the rate

for framing. For finding the cost of lamination, we need to find the area and then multiply it by the

rate for lamination.

What would you need to find, area or perimeter, to answer the following?

1. How much space does a blackboard occupy?

2. What is the length of a wire required to fence a rectangular flower bed?

3. What distance would you cover by taking two rounds of a triangular park?

4. How much plastic sheet do you need to cover a rectangular swimming pool?

Do you remember,

The perimeter of a regular polygon = number of sides × length of one side

The perimeter of a square = 4 × side

Perimeter of a rectangle = 2 × (l + b)

Area of a rectangle = l × b, Area of a square = side × side

WHAT HAVE WE DISCUSSED?

1. Perimeter is the distance around a closed figure whereas area is the part of the plane

occupied by the closed figure.

2. We have learnt how to find the perimeter and area of a square and rectangle in the earlier

class. They are:

(a) Perimeter of a square = 4 × side

(b) Perimeter of a rectangle = 2 × (length + breadth)

(d) Area of a rectangle = length × breadth