NCERT Solutions For Class 6 Maths Chapter 3 Exercise 3.1
Ncert Solutions for Class 6 Maths Chapter 3 Playing With Numbers Exercise 3.1:
Ncert Solutions for Class 6 Maths Chapter 3 Playing with Numbers Exercise 3.1 pdf: In this Chapter playing with numbers We learn the basics of the Numbers System In class 6 maths ncert Exercise 3.1 Solutions. This Chapter Playing with Numbers is very important for Students to get a High Score in their Exam. And we help the Students to Achieve Their Dream By providing Class 6 Maths Ncert Solutions Chapter 3 Playing with Numbers Exercise 3.1 With Free Pdf Download. And We also Provide link Video solutions in pdf of Each Exercise
Ncert Solutions for Class 6 Maths Chapter 3 Playing with Numbers Exercise 3.1 pdf:-
Exercise 3.1 Class 6 maths NCERT solutions Chapter 3 Playing with Numbers Numbers pdf download:-
Ncert Solution for Class 6 Maths Chapter 3 Playing Numbers Exercise 3.1 Tips:-
Introduction-
Ramesh has 6 marbles with him. He wants to arrange them in rows in such a way
that each row has the same number of marbles. He arranges them in the following
ways and matches the total number of marbles.
(i) 1 marble in each row
Number of rows = 6
Total number of marbles = 1 × 6 = 6
(ii) 2 marbles in each row
Number of rows = 3
Total number of marbles = 2 × 3 = 6
(iii) 3 marbles in each row
Number of rows = 2
Total number of marbles = 3 × 2 = 6
(iv) He could not think of any arrangement in which each row had 4 marbles or
5 marbles. So, the only possible arrangement left was with all the 6 marbles
in a row.
Number of rows = 1
Total number of marbles = 6 × 1 = 6
From these calculations Ramesh observes that 6 can be written as a product
of two numbers in different ways as
6 = 1 × 6; 6 = 2 × 3; 6 = 3 × 2; 6 = 6 × 1
From 6 = 2 × 3 it can be said that 2 and 3 exactly divide 6. So, 2 and 3 are
the exact divisors of 6. From the other product 6 = 1 × 6, the exact divisors of 6 are
found to be 1 and 6.
Thus, 1, 2, 3 and 6 are exact divisors of 6. They are called the factors of 6.
Try arranging 18 marbles in rows and find the factors of 18.
Factors and Multiples
Mary wants to find those numbers which exactly divide 4. She divides 4 by
numbers less than 4 this way.
Quotient is 4 Remainder is 0 4 = 1 × 4
Quotient is 2 Remainder is 0 4 = 2 × 2
Quotient is 1 Remainder is 1
Quotient is 1 Remainder is 0 4 = 4 × 1
She finds that the number 4 can be written as: 4 = 1 × 4; 4 = 2 × 2;
4 = 4 × 1 and knows that the numbers 1, 2 and 4 are exact divisors of 4.
These numbers are called factors of 4.
A factor of a number is an exact divisor of that number.
Observe each of the factors of 4 is less than or equal to 4.
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