## Ncert Solutions for Class 6 Maths Chapter 3 Playing With Numbers Exercise 3.1:

**Ncert Solutions for Class 6 Maths Chapter 3 Playing with Numbers Exercise 3.1 pdf:Ā**In this Chapter playing with numbers We learn the basics of the Numbers System In class 6 maths ncert Exercise 3.1 Solutions. This Chapter Playing with Numbers is very important for Students to get a High Score in their Exam. And we help the Students to Achieve Their Dream By providing Class 6 Maths Ncert Solutions Chapter 3 Playing with Numbers Exercise 3.1 With Free Pdf Download. And We also Provide link Video solutions in pdf of Each Exercise

### Ncert Solutions for Class 6 Maths Chapter 3 Playing with Numbers Exercise 3.1 pdf:-

**Exercise 3.1**Ā Class 6 maths NCERT solutions Chapter 3 Playing with Numbers Numbers pdf download:-

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### Ncert Solution for Class 6 Maths Chapter 3 PlayingĀ Numbers Exercise 3.1 Tips:-

**Introduction-**

Ramesh has 6 marbles with him. He wants to arrange them in rows in such a way

that each row has the same number of marbles. He arranges them in the following

ways and matches the total number of marbles.

(i) 1 marble in each row

Number of rows = 6

Total number of marbles = 1 Ć 6 = 6

(ii) 2 marbles in each row

Number of rows = 3

Total number of marbles = 2 Ć 3 = 6

(iii) 3 marbles in each row

Number of rows = 2

Total number of marbles = 3 Ć 2 = 6

(iv) He could not think of any arrangement in which each row had 4 marbles or

5 marbles. So, the only possible arrangement left was with all the 6 marbles

in a row.

Number of rows = 1

Total number of marbles = 6 Ć 1 = 6

From these calculations Ramesh observes that 6 can be written as a product

of two numbers in different ways as

6 = 1 Ć 6; 6 = 2 Ć 3; 6 = 3 Ć 2; 6 = 6 Ć 1

From 6 = 2 Ć 3 it can be said that 2 and 3 exactly divide 6. So, 2 and 3 are

the exact divisors of 6. From the other product 6 = 1 Ć 6, the exact divisors of 6 are

found to be 1 and 6.

Thus, 1, 2, 3 and 6 are exact divisors of 6. They are called the factors of 6.

Try arranging 18 marbles in rows and find the factors of 18.

**Factors and Multiples**

Mary wants to find those numbers which exactly divide 4. She divides 4 by

numbers less than 4 this way.

Quotient is 4 Remainder is 0Ā 4 = 1 Ć 4

Quotient is 2 Remainder is 0Ā 4 = 2 Ć 2

Quotient is 1 Remainder is 1

Quotient is 1 Remainder is 0Ā 4 = 4 Ć 1

She finds that the number 4 can be written as: 4 = 1 Ć 4; 4 = 2 Ć 2;

4 = 4 Ć 1 and knows that the numbers 1, 2 and 4 are exact divisors of 4.

These numbers are called factors of 4.

A factor of a number is an exact divisor of that number.

Observe each of the factors of 4 is less than or equal to 4.