NCERT Solutions For Class 6 Maths Chapter 7 Exercise 7.4

Ncert Solutions for Class 6 Maths Chapter 7 Fractions Exercise 7.4:-

Ncert Solutions for Class 6 Maths Chapter 7 Fractions Exercise 7.4
Exercise 7.4 Class 6 maths NCERT solutions Chapter 7 Basic Geometrical Ideas pdf download:-
 

Ncert Solution for Class 6 Maths Chapter 7 Fractions Exercise 7.4 Tipss:-

Comparing like fractions
In both the fractions the whole is divided into 8 equal parts. For 3
8 and 5
8 ,
we take 3 and 5 parts respectively out of the 8 equal parts. Clearly, out of 8
equal parts, the portion corresponding to 5 parts is larger than the portion
corresponding to 3 parts. Hence, 5
8
>
3
8 . Note the number of the parts taken is
given by the numerator. It is, therefore, clear that for two fractions with the
same denominator, the fraction with the greater numerator is greater. Between
4
5 and 3
5 , 4
5 is greater. Between 11
20 and 13
20 , 13
20 is greater and so on.
In
1
3 , we divide the whole into 3 equal parts and take one. In 1
 
5 , we divide the
 
whole into 5 equal parts and take one. Note that in 1
 
3 , the whole is divided into
 
a smaller number of parts than in 1
 
5 . The equal part that we get in 1
 
3 is, therefore,
 
larger than the equal part we get in 1
 
5 . Since in both cases we take the same
 
number of parts (i.e. one), the portion of the whole showing 1
 
3 is larger than the
 
portion showing 1
 
5 , and therfore 1
In the same way we can say 2
> . In this case, the situation is the same as in
the case above, except that the common numerator is 2, not 1. The whole is
divided into a large number of equal parts for 2
 
5 than for 2
 
3 . Therefore, each
 
equal part of the whole in case of 2
 
3 is larger than that in case of 2
 
5 . Therefore,
 
the portion of the whole showing 2
 
3 is larger than the portion showing 2
5 and
We can see from the above example that if the numerator is the same in
two fractions, the fraction with the smaller denominator is greater of the two.
Thus, 1
Let us arrange
, in increasing order. All these fractions are
unlike, but their numerator is the same. Hence, in such case, the larger the
denominator, the smaller is the fraction. The smallest is 2
 
13 , as it has the
 
largest denominator. The next three fractions in order are 2
 The greatest
 
fraction is 2
 
1 (It is with the smallest denominator). The arrangement in
 
increasing order, therefore, is 2
Suppose we want to compare 2
3 and 3
4 . Their numerators are different
and so are their denominators. We know how to compare like fractions, i.e.
fractions with the same denominator. We should, therefore, try to change the
denominators of the given fractions, so that they become equal. For this
purpose, we can use the method of equivalent fractions which we already
know. Using this method we can change the denominator of a fraction without
changing its value.
Answers

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